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Limits Continuity and Differentiability question

2016 · 9 Apr · Shift 1 · Q45

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JEE Main
Mathematics
Limits Continuity and Differentiability
2016 · 9 Apr · Shift 1 · Q45

Limits Continuity and Differentiability question

2016 · 9 Apr · Shift 1 · Q45

JEE MainMathematicsLimits Continuity and DifferentiabilityMCQ+4 / −1

If the function f(x) =

\left\{ {\begin{matrix} { - x} & {x \lt 1} \\ {a + {{\cos }^{ - 1}}\left( {x + b} \right),} & {1 \le x \le 2} \\ \end{matrix} } \right.

is differentiable at x = 1, then

{a \over b}

is equal to :

A
${{\pi - 2} \over 2}$
B
${{ - \pi - 2} \over 2}$
C
${{\pi + 2} \over 2}$
D
$- 1 - {\cos ^{ - 1}}\left( 2 \right)$

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