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Limits Continuity and Differentiability question

2017 · 9 Apr · Shift 1 · Q39
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  5. /2017 · 9 Apr · Shift 1 · Q39

Limits Continuity and Differentiability question

2017 · 9 Apr · Shift 1 · Q39

JEE MainMathematicsLimits Continuity and DifferentiabilityMCQ+4 / −1
The value of k for which the function f(x)={(45)tan⁡ 4xtan⁡ 5x  ,0<x<π2k+25   ,x=π2f\left( x \right) = \left\{ {\begin{matrix} {{{\left( {{4 \over 5}} \right)}^{{{\tan \,4x} \over {\tan \,5x}}}}\,\,,} & {0 \lt x \lt {\pi \over 2}} \\ {k + {2 \over 5}\,\,\,,} & {x = {\pi \over 2}} \\ \end{matrix} } \right.f(x)={(54​)tan5xtan4x​,k+52​,​0<x<2π​x=2π​​ is continuous at x =π2,{\pi \over 2},2π​, is :
  1. A
    1720{{17} \over {20}}2017​
  2. B
    25{{2} \over {5}}52​
  3. C
    35{{3} \over {5}}53​
  4. D
    −25-{{2} \over {5}}−52​
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