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Indefinite Integrals question

2020 · 5 Sep · Shift 2 · Q30
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  5. /2020 · 5 Sep · Shift 2 · Q30

Indefinite Integrals question

2020 · 5 Sep · Shift 2 · Q30

JEE MainMathematicsIndefinite IntegralsMCQ+4 / −1
If ∫cos⁡θ5+7sin⁡θ−2cos⁡2θdθ\int {{{\cos \theta } \over {5 + 7\sin \theta - 2{{\cos }^2}\theta }}} d\theta∫5+7sinθ−2cos2θcosθ​dθ= A log⁡e∣B(θ)∣+C{\log _e}\left| {B\left( \theta \right)} \right| + Cloge​∣B(θ)∣+C, where C is a constant of integration, then B(θ)A{{{B\left( \theta \right)} \over A}}AB(θ)​ can be :
  1. A
    2sin⁡θ+15(sin⁡θ+3){{2\sin \theta + 1} \over {5\left( {\sin \theta + 3} \right)}}5(sinθ+3)2sinθ+1​
  2. B
    2sin⁡θ+1sin⁡θ+3{{2\sin \theta + 1} \over {\sin \theta + 3}}sinθ+32sinθ+1​
  3. C
    5(2sin⁡θ+1)sin⁡θ+3{{5\left( {2\sin \theta + 1} \right)} \over {\sin \theta + 3}}sinθ+35(2sinθ+1)​
  4. D
    5(sin⁡θ+3)2sin⁡θ+1{{5\left( {\sin \theta + 3} \right)} \over {2\sin \theta + 1}}2sinθ+15(sinθ+3)​
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