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Indefinite Integrals question

2020 · 5 Sep · Shift 1 · Q24
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  5. /2020 · 5 Sep · Shift 1 · Q24

Indefinite Integrals question

2020 · 5 Sep · Shift 1 · Q24

JEE MainMathematicsIndefinite IntegralsMCQ+4 / −1
If ∫(e2x+2ex−e−x−1)e(ex+e−x)dx\int {\left( {{e^{2x}} + 2{e^x} - {e^{ - x}} - 1} \right){e^{\left( {{e^x} + {e^{ - x}}} \right)}}dx}∫(e2x+2ex−e−x−1)e(ex+e−x)dx=g(x)e(ex+e−x)+cg\left( x \right){e^{\left( {{e^x} + {e^{ - x}}} \right)}} + cg(x)e(ex+e−x)+c where c is a constant of integration, then g(0) is equal to :
  1. A
    1
  2. B
    2
  3. C
    e
  4. D
    e2
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