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Indefinite Integrals question

2019 · 8 Apr · Shift 2 · Q45
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  5. /2019 · 8 Apr · Shift 2 · Q45

Indefinite Integrals question

2019 · 8 Apr · Shift 2 · Q45

JEE MainMathematicsIndefinite IntegralsMCQ+4 / −1
If ∫dxx3(1+x6)2/3=xf(x)(1+x6)13+C\int {{{dx} \over {{x^3}{{(1 + {x^6})}^{2/3}}}} = xf(x){{(1 + {x^6})}^{{1 \over 3}}} + C}∫x3(1+x6)2/3dx​=xf(x)(1+x6)31​+C where C is a constant of integration, then the function ƒ(x) is equal to
  1. A
    3x2{3 \over {{x^2}}}x23​
  2. B
    −16x3- {1 \over {6{x^3}}}−6x31​
  3. C
    −12x3- {1 \over {2{x^3}}}−2x31​
  4. D
    −12x2- {1 \over {2{x^2}}}−2x21​
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