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Indefinite Integrals question

2020 · 9 Jan · Shift 2 · Q26

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PYQ Library
JEE Main
Mathematics
Indefinite Integrals
2020 · 9 Jan · Shift 2 · Q26

Indefinite Integrals question

2020 · 9 Jan · Shift 2 · Q26

JEE MainMathematicsIndefinite IntegralsMCQ+4 / −1

If

\int {{{d\theta } \over {{{\cos }^2}\theta \left( {\tan 2\theta + \sec 2\theta } \right)}}} = \lambda \tan \theta + 2{\log _e}\left| {f\left( \theta \right)} \right| + C

where C is a constant of integration, then the ordered pair (

\lambda

, ƒ(

\theta

)) is equal to :

A
(–1, 1 – tan $\theta$ )
B
(1, 1 + tan $\theta$ )
C
(–1, 1 + tan $\theta$ )
D
(1, 1 – tan $\theta$ )

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