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3D Geometry question

2025 · 7 Apr · Shift 2 · Q35
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  5. /2025 · 7 Apr · Shift 2 · Q35

3D Geometry question

2025 · 7 Apr · Shift 2 · Q35

JEE MainMathematics3D GeometryMCQ+4 / −1
If the equation of the line passing through the point (0,−12,0)\left( 0, -\frac{1}{2}, 0 \right)(0,−21​,0) and perpendicular to the lines r⃗=λ(i^+aj^+bk^)\vec{r} = \lambda \left( \hat{i} + a\hat{j} + b\hat{k} \right)r=λ(i^+aj^​+bk^) and r⃗=(i^−j^−6k^)+μ(−bi^+aj^+5k^)\vec{r} = \left( \hat{i} - \hat{j} - 6\hat{k} \right) + \mu \left( -b \hat{i} + a\hat{j} + 5\hat{k} \right)r=(i^−j^​−6k^)+μ(−bi^+aj^​+5k^) is x−1−2=y+4d=z−c−4\frac{x-1}{-2} = \frac{y+4}{d} = \frac{z-c}{-4}−2x−1​=dy+4​=−4z−c​, then a+b+c+da+b+c+da+b+c+d is equal to :
  1. A
    13
  2. B
    14
  3. C
    12
  4. D
    10
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