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3D Geometry question

2025 · 22 Jan · Shift 2 · Q31
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  5. /2025 · 22 Jan · Shift 2 · Q31

3D Geometry question

2025 · 22 Jan · Shift 2 · Q31

JEE MainMathematics3D GeometryMCQ+4 / −1
The perpendicular distance, of the line x−12=y+2−1=z+32\frac{x-1}{2}=\frac{y+2}{-1}=\frac{z+3}{2}2x−1​=−1y+2​=2z+3​ from the point P(2,−10,1)\mathrm{P}(2,-10,1)P(2,−10,1), is :
  1. A
    666
  2. B
    434 \sqrt{3}43​
  3. C
    353 \sqrt{5}35​
  4. D
    525 \sqrt{2}52​
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