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3D Geometry question

2025 · 7 Apr · Shift 1 · Q42

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JEE Main
Mathematics
3D Geometry
2025 · 7 Apr · Shift 1 · Q42

3D Geometry question

2025 · 7 Apr · Shift 1 · Q42

JEE MainMathematics3D GeometryMCQ+4 / −1

If the shortest distance between the lines

\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}

and

\frac{x}{1}=\frac{y}{\alpha}=\frac{z-5}{1}

is

\frac{5}{\sqrt{6}}

, then the sum of all possible values of

\alpha

is

A
$\frac{3}{2}$
B
$3$
C
$-3$
D
$-\frac{3}{2}$

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