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3D Geometry question

2025 · 8 Apr · Shift 2 · Q49

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JEE Main
Mathematics
3D Geometry
2025 · 8 Apr · Shift 2 · Q49

3D Geometry question

2025 · 8 Apr · Shift 2 · Q49

JEE MainMathematics3D GeometryNumerical+4 / −1

Let the area of the triangle formed by the lines

x+2=y-1=z, \frac{x-3}{5}=\frac{y}{-1}=\frac{z-1}{1}

and

\frac{x}{-3}=\frac{y-3}{3}=\frac{z-2}{1}

be

A

. Then

A^2

is equal to

\underline{\hspace{2cm}}

.

Numerical answer

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