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3D Geometry question

2025 · 22 Jan · Shift 1 · Q28
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  5. /2025 · 22 Jan · Shift 1 · Q28

3D Geometry question

2025 · 22 Jan · Shift 1 · Q28

JEE MainMathematics3D GeometryMCQ+4 / −1
Let L1:x−12=y−23=z−34\mathrm{L}_1: \frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}L1​:2x−1​=3y−2​=4z−3​ and L2:x−23=y−44=z−55\mathrm{L}_2: \frac{x-2}{3}=\frac{y-4}{4}=\frac{z-5}{5}L2​:3x−2​=4y−4​=5z−5​ be two lines. Then which of the following points lies on the line of the shortest distance between L1\mathrm{L}_1L1​ and L2\mathrm{L}_2L2​ ?
  1. A
    (143,−3,223)\left(\frac{14}{3},-3, \frac{22}{3}\right)(314​,−3,322​)
  2. B
    (2,3,13)\left(2,3, \frac{1}{3}\right)(2,3,31​)
  3. C
    (83,−1,13)\left(\frac{8}{3},-1, \frac{1}{3}\right)(38​,−1,31​)
  4. D
    (−53,−7,1)\left(-\frac{5}{3},-7,1\right)(−35​,−7,1)
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