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3D Geometry question

2025 · 23 Jan · Shift 1 · Q27
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  5. /2025 · 23 Jan · Shift 1 · Q27

3D Geometry question

2025 · 23 Jan · Shift 1 · Q27

JEE MainMathematics3D GeometryMCQ+4 / −1
Let P be the foot of the perpendicular from the point Q(10,−3,−1)\mathrm{Q}(10,-3,-1)Q(10,−3,−1) on the line x−37=y−2−1=z+1−2\frac{x-3}{7}=\frac{y-2}{-1}=\frac{z+1}{-2}7x−3​=−1y−2​=−2z+1​. Then the area of the right angled triangle PQRP Q RPQR, where RRR is the point (3,−2,1)(3,-2,1)(3,−2,1), is
  1. A
    30\sqrt{30}30​
  2. B
    9159 \sqrt{15}915​
  3. C
    3303 \sqrt{30}330​
  4. D
    8158 \sqrt{15}815​
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