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Thermodynamics question

2024 · 1 Feb · Shift 2 · Q25
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Thermodynamics question

2024 · 1 Feb · Shift 2 · Q25

JEE MainChemistryThermodynamicsNumerical+4 / −1
For a certain reaction at 300 K, K=10300 \mathrm{~K}, \mathrm{~K}=10300 K, K=10, then ΔG∘\Delta \mathrm{G}^{\circ}ΔG∘ for the same reaction is - ‾\underline{\hspace{2cm}}​×10−1 kJ mol−1\times 10^{-1} \mathrm{~kJ} \mathrm{~mol}^{-1}×10−1 kJ mol−1. (Given R=8.314JK−1 mol−1\mathrm{R}=8.314 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}R=8.314JK−1 mol−1 )
Numerical answer
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