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Thermodynamics question

2024 · 5 Apr · Shift 1 · Q6
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  5. /2024 · 5 Apr · Shift 1 · Q6

Thermodynamics question

2024 · 5 Apr · Shift 1 · Q6

JEE MainChemistryThermodynamicsMCQ+4 / −1
Given below are two statements: One is labelled as Assertion (A) and the other is labelled as Reason (R) Assertion (A) : Enthalpy of neutralisation of strong monobasic acid with strong monoacidic base is always −57 kJ mol−1-57 \mathrm{~kJ} \mathrm{~mol}^{-1}−57 kJ mol−1 Reason (R) : Enthalpy of neutralisation is the amount of heat liberated when one mole of H+\mathrm{H}^{+}H+ ions furnished by acid combine with one mole of −OH{ }^{-} \mathrm{OH}−OH ions furnished by base to form one mole of water. In the light of the above statements, choose the correct answer from the options given below.
  1. A
    (A) is true but (R) is false
  2. B
    Both (A) and (R) are true and (R) is the correct explanation of (A)
  3. C
    Both (A) and (R) are true but (R) is not the correct explanation of (A)
  4. D
    (A) is false but (R) is true
View written solutionFree

Correct answer: B

  1. Analyze the Assertion (A)

    Assertion: Enthalpy of neutralisation of strong monobasic acid with strong monoacidic base is always −57 kJ mol−1-57\,\text{kJ mol}^{-1}−57kJ mol−1.

    For a strong acid and a strong base, both are almost completely ionised in aqueous solution: HCl→H++Cl−\mathrm{HCl \rightarrow H^+ + Cl^-}HCl→H++Cl− NaOH→Na++OH−\mathrm{NaOH \rightarrow Na^+ + OH^-}NaOH→Na++OH−

    So the actual net ionic reaction is: H+(aq)+OH−(aq)→H2O(l)\mathrm{H^+ (aq) + OH^- (aq) \rightarrow H_2O(l)}H+(aq)+OH−(aq)→H2​O(l)

    The enthalpy change for this reaction is nearly constant and is approximately: ΔHneut≈−57 kJ mol−1\Delta H_{\text{neut}} \approx -57\,\text{kJ mol}^{-1}ΔHneut​≈−57kJ mol−1

    Hence, Assertion (A) is true.

  2. Analyze the Reason (R)

    Reason: Enthalpy of neutralisation is the amount of heat liberated when one mole of H+\mathrm{H^+}H+ ions furnished by acid combine with one mole of OH−\mathrm{OH^-}OH− ions furnished by base to form one mole of water.

    This is the standard definition of enthalpy of neutralisation.

    Therefore, Reason (R) is true.

  3. Check whether (R) explains (A)

    In the case of strong acid and strong base, the acid and base are fully dissociated. So neutralisation always reduces to the same ionic reaction: H++OH−→H2O\mathrm{H^+ + OH^- \rightarrow H_2O}H++OH−→H2​O

    Since the same process occurs in every such case, the enthalpy of neutralisation remains the same, about: −57 kJ mol−1-57\,\text{kJ mol}^{-1}−57kJ mol−1

    Thus, (R) correctly explains (A).

  4. Correct option

    Therefore, the correct answer is: B: Both (A) and (R) are true and (R) is the correct explanation of (A).

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