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Some Basic Concepts of Chemistry question

2023 · 31 Jan · Shift 1 · Q16
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Some Basic Concepts of Chemistry question

2023 · 31 Jan · Shift 1 · Q16

JEE MainChemistrySome Basic Concepts of ChemistryNumerical+4 / −1
Zinc reacts with hydrochloric acid to give hydrogen and zinc chloride. The volume of hydrogen gas produced at STP from the reaction of 11.5 g11.5 \mathrm{~g}11.5 g of zinc with excess HCl\mathrm{HCl}HCl is ‾\underline{\hspace{2cm}}​ L (Nearest integer) (Given : Molar mass of Zn\mathrm{Zn}Zn is 65.4 g mol−165.4 \mathrm{~g} \mathrm{~mol}^{-1}65.4 g mol−1 and Molar volume of H2\mathrm{H}_{2}H2​ at STP=22.7 L\mathrm{STP}=22.7 \mathrm{~L}STP=22.7 L )
Numerical answer
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Correct answer: 4

  1. Write the balanced chemical reaction

Zn+2HCl→ZnCl2+H2\mathrm{Zn + 2HCl \rightarrow ZnCl_2 + H_2}Zn+2HCl→ZnCl2​+H2​

From the equation:

  • 111 mole of Zn\mathrm{Zn}Zn produces 111 mole of H2\mathrm{H_2}H2​.
  1. Calculate moles of zinc

Given mass of zinc = 11.5 g11.5\,\mathrm{g}11.5g

Molar mass of zinc = 65.4 g mol−165.4\,\mathrm{g\,mol^{-1}}65.4gmol−1

n(Zn)=11.565.4n(\mathrm{Zn})=\frac{11.5}{65.4}n(Zn)=65.411.5​

n(Zn)≈0.176 moln(\mathrm{Zn})\approx 0.176\,\mathrm{mol}n(Zn)≈0.176mol

  1. Use stoichiometry to find moles of hydrogen

Since 111 mole of Zn\mathrm{Zn}Zn gives 111 mole of H2\mathrm{H_2}H2​,

n(H2)=0.176 moln(\mathrm{H_2}) = 0.176\,\mathrm{mol}n(H2​)=0.176mol

  1. Calculate volume of hydrogen at STP

Given molar volume at STP = 22.7 L mol−122.7\,\mathrm{L\,mol^{-1}}22.7Lmol−1

V(H2)=n×22.7V(\mathrm{H_2}) = n \times 22.7V(H2​)=n×22.7

V(H2)=0.176×22.7V(\mathrm{H_2}) = 0.176 \times 22.7V(H2​)=0.176×22.7

V(H2)≈3.995 LV(\mathrm{H_2}) \approx 3.995\,\mathrm{L}V(H2​)≈3.995L

  1. Nearest integer

V≈4 LV \approx 4\,\mathrm{L}V≈4L

Hence, the required answer is 444 L.

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