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Some Basic Concepts of Chemistry question

2023 · 30 Jan · Shift 2 · Q15
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Some Basic Concepts of Chemistry question

2023 · 30 Jan · Shift 2 · Q15

JEE MainChemistrySome Basic Concepts of ChemistryNumerical+4 / −1
The strength of 50 volume solution of hydrogen peroxide is ‾g/L\underline{\hspace{2cm}}\mathrm{g} / \mathrm{L}​g/L(Nearest integer). Given: Molar mass of H2O2\mathrm{H}_{2} \mathrm{O}_{2}H2​O2​ is 34 g mol−134 \mathrm{~g} \mathrm{~mol}^{-1}34 g mol−1 Molar volume of gas at STP=22.7 L\mathrm{STP}=22.7 \mathrm{~L}STP=22.7 L
Numerical answer
View written solutionFree

Correct answer: 150

  1. Meaning of volume strength

A 505050 volume solution of hydrogen peroxide means:

  • 1\,\text{L}$ of solution gives 50,\text{L} of $$O_2 at STP.
  1. Decomposition reaction of hydrogen peroxide

2H2O2→2H2O+O22H_2O_2 \rightarrow 2H_2O + O_22H2​O2​→2H2​O+O2​

From the reaction:

  • $2 mol H_2O_2$ produce `$1` mol O_2$.
  1. Moles of oxygen produced by 1 L solution

Given molar volume at STP = $$22.7,\text{L mol}^{-1}$

So moles of O_2$ corresponding to 50,\text{L}$ are:

n(O2)=5022.7n(O_2)=\frac{50}{22.7}n(O2​)=22.750​

  1. Moles of hydrogen peroxide required

Using stoichiometry:

n(H2O2)=2×5022.7=10022.7n(H_2O_2)=2\times \frac{50}{22.7}=\frac{100}{22.7}n(H2​O2​)=2×22.750​=22.7100​

  1. Mass of hydrogen peroxide in 1 L solution

Molar mass of $$H_2O_2 = 34,\text{g mol}^{-1}$

Mass=10022.7×34\text{Mass} = \frac{100}{22.7}\times 34Mass=22.7100​×34

Mass≈149.78 g\text{Mass} \approx 149.78\,\text{g}Mass≈149.78g

Nearest integer:

150 g/L\boxed{150\,\text{g/L}}150g/L​

  1. Comparison with stored correct answer

Stored correct answer = $150.

Our derived answer matches the stored answer.

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