JEE MainChemistrySome Basic Concepts of ChemistryMCQ+4 / −1
on reaction with excess of water results into acidic mixture 16 moles of is required for the complete neutralisation of the resultant acidic mixture. The number of moles of used is :
- A16
- B8
- C4
- D2
View written solutionFree
Correct answer: C
- The reaction of sulfuryl chloride with excess water is:
- For each mole of , the acidic products formed are:
- mole of
- moles of
- Now calculate how many moles of are needed to neutralize these acids.
-
Neutralization of sulfuric acid:
So, mole of requires moles of .
-
Neutralization of hydrochloric acid:
So, moles of require moles of .
- Therefore, total required per mole of is:
So,
- Given that moles of are required:
- Hence, the correct option is:
More from Some Basic Concepts of Chemistry
- 56.0 L of nitrogen gas is mixed with excess hydrogen gas and it is found that 20 L of ammonia gas is produced. The volume of unused nitrogen gas is found to be L.2022 · Numerical
- A sample of 4.5 mg of an unknown monohydric alcohol, was added to methylmagnesium iodide. A gas is evolved and is collected and its volume measured to be 3.1 mL. The molecular weight of the unknown alcohol is …2022 · Numerical
- The number of N atoms in 681 g of is x 1021. The value of x is (NA = 6.02 1023 mol 1) (Nearest Integer)2022 · Numerical
- 1 L aqueous solution of contains 0.02 m mol . 50% of this solution is diluted with deionized water to give 1 L solution (A). In solution (A), 0.01 m mol of are added. Total m mols of in the final…2022 · Numerical
- Number of grams of bromine that will completely react with 5.0 g of pent-1-ene is 10 2 g. (Atomic mass of Br = 80 g/mol) [Nearest Integer]2022 · Numerical
- A protein 'A' contains 0.30% of glycine (molecular weight 75). The minimum molar mass of the protein 'A' is 103 g mol 1 [nearest integer]2022 · Numerical
- Chlorophyll extracted from the crushed green leaves was dissolved in water to make solution of Mg of concentration . The number of atoms of in this solution is atoms. The…2022 · Numerical
- When 800 mL of 0.5 M nitric acid is heated in a beaker, its volume is reduced to half and 11.5 g of nitric acid is evaporated. The molarity of the remaining nitric acid solution is x 10 2 M. (Nearest integer) (Molar mass of…2022 · Numerical