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Practical Organic Chemistry question

2024 · 30 Jan · Shift 1 · Q29
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Practical Organic Chemistry question

2024 · 30 Jan · Shift 1 · Q29

JEE MainChemistryPractical Organic ChemistryNumerical+4 / −1
On a thin layer chromatographic plate, an organic compound moved by 3.5 cm3.5 \mathrm{~cm}3.5 cm, while the solvent moved by 5 cm5 \mathrm{~cm}5 cm. The retardation factor of the organic compound is ‾×10−1\underline{\hspace{2cm}}\times 10^{-1}​×10−1.
Numerical answer
View written solutionFree

Correct answer: 7

  1. In thin layer chromatography (TLC), the retardation factor RfR_fRf​ is defined as

Rf=distance travelled by the compounddistance travelled by the solvent frontR_f = \frac{\text{distance travelled by the compound}}{\text{distance travelled by the solvent front}}Rf​=distance travelled by the solvent frontdistance travelled by the compound​

  1. Given:
  • Distance travelled by compound =3.5 cm= 3.5\,\text{cm}=3.5cm
  • Distance travelled by solvent front =5 cm= 5\,\text{cm}=5cm

So,

Rf=3.55=0.7R_f = \frac{3.5}{5} = 0.7Rf​=53.5​=0.7

  1. Now express 0.70.70.7 in the form _×10−1\_ \times 10^{-1}_×10−1:

0.7=7×10−10.7 = 7 \times 10^{-1}0.7=7×10−1

  1. Therefore, the required integer is

7\boxed{7}7​

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