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Practical Organic Chemistry question

2023 · 6 Apr · Shift 1 · Q13
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Practical Organic Chemistry question

2023 · 6 Apr · Shift 1 · Q13

JEE MainChemistryPractical Organic ChemistryMCQ+4 / −1

Match List I with List II

LIST I
Element detected		 LIST II
Reagent used / Product formed
A. Nitrogen I. Na2[Fe(CN)5NO]\mathrm{Na_2[Fe(CN)_5NO]}Na2​[Fe(CN)5​NO]
B. Sulphur II. AgNO3\mathrm{AgNO_3}AgNO3​
C. Phosphorous III. Fe4[Fe(CN)6]3\mathrm{Fe_4[Fe(CN)_6]_3}Fe4​[Fe(CN)6​]3​
D. Halogen IV. (NH4)2MoO4\mathrm{(NH_4)_2MoO_4}(NH4​)2​MoO4​

Choose the correct answer from the options given below:

  1. A
    A-III, B-I, C-IV, D-II
  2. B
    A-II, B-I, C-IV, D-III
  3. C
    A-IV, B-II, C-I, D-III
  4. D
    A-II, B-IV, C-I, D-III
View written solutionFree

Correct answer: A

  1. Identify the standard test for each element in practical organic analysis

    In Lassaigne's test:

    • Nitrogen is detected by formation of Prussian blue.
    • Sulphur is detected using sodium nitroprusside.
    • Phosphorus is detected using ammonium molybdate.
    • Halogen is detected using silver nitrate.

  2. Match each item

    A. Nitrogen

    Nitrogen in Lassaigne's extract gives ferrocyanide, which on reaction produces Prussian blue: Fe4[Fe(CN)6]3\mathrm{Fe_4[Fe(CN)_6]_3}Fe4​[Fe(CN)6​]3​ So, A→IIIA \to IIIA→III

    B. Sulphur

    Sulphur gives violet coloration with sodium nitroprusside: Na2[Fe(CN)5NO]\mathrm{Na_2[Fe(CN)_5NO]}Na2​[Fe(CN)5​NO] So, B→IB \to IB→I

    C. Phosphorous

    Phosphorus is detected using ammonium molybdate: (NH4)2MoO4\mathrm{(NH_4)_2MoO_4}(NH4​)2​MoO4​ So, C→IVC \to IVC→IV

    D. Halogen

    Halogens are detected with silver nitrate: AgNO3\mathrm{AgNO_3}AgNO3​ So, D→IID \to IID→II

  3. Final matching

    A−III,  B−I,  C−IV,  D−IIA-III,\; B-I,\; C-IV,\; D-IIA−III,B−I,C−IV,D−II

  4. Compare with options

    This corresponds to Option A.

  5. Comparison with stored correct answer

    Stored correct answer = A

    Our derived answer = A

    Hence, the answer agrees.

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