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Practical Organic Chemistry question

2024 · 8 Apr · Shift 2 · Q16
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Practical Organic Chemistry question

2024 · 8 Apr · Shift 2 · Q16

JEE MainChemistryPractical Organic ChemistryMCQ+4 / −1

Match List I with List II

LIST I
(Test)		 LIST II
(Identification)
A. Bayer's test I. Phenol
B. Ceric ammonium nitrate test II. Aldehyde
C. Phthalein dye test III. Alcoholic-OH group
D. Schiff's test IV. Unsaturation

Choose the correct answer from the options given below :

  1. A
    (A)-(IV), (B)-(I), (C)-(II), (D)-(III)
  2. B
    (A)-(III), (B)-(I), (C)-(IV), (D)-(II)
  3. C
    (A)-(II), (B)-(III), (C)-(IV), (D)-(I)
  4. D
    (A)-(IV), (B)-(III), (C)-(I), (D)-(II)
View written solutionFree

Correct answer: D

  1. Identify each test in List I

    We match each qualitative organic test with the functional group it identifies.

  2. Bayer's test

    • Bayer's reagent is dilute alkaline KMnO4KMnO_4KMnO4​.
    • It is used to detect unsaturation (C=CC=CC=C, C≡CC\equiv CC≡C).

    Therefore, A→IVA \rightarrow IVA→IV

  3. Ceric ammonium nitrate test

    • Ceric ammonium nitrate gives a characteristic color with compounds containing an alcoholic hydroxyl group.

    Therefore, B→IIIB \rightarrow IIIB→III

  4. Phthalein dye test

    • Phenols react with phthalic anhydride in presence of concentrated H2SO4H_2SO_4H2​SO4​ to form phthalein dyes.
    • Hence this test is used for phenol.

    Therefore, C→IC \rightarrow IC→I

  5. Schiff's test

    • Schiff's reagent gives a pink/magenta color with aldehydes.

    Therefore, D→IID \rightarrow IID→II

  6. Final matching

    A−IV,  B−III,  C−I,  D−IIA-IV,\; B-III,\; C-I,\; D-IIA−IV,B−III,C−I,D−II

  7. Compare with options

    This corresponds to Option D.

  8. Comparison with stored answer

    Stored correct answer = D.

    Our derived answer matches the stored answer.

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