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Practical Organic Chemistry question

2024 · 9 Apr · Shift 2 · Q16
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Practical Organic Chemistry question

2024 · 9 Apr · Shift 2 · Q16

JEE MainChemistryPractical Organic ChemistryMCQ+4 / −1

Match List I with List II

LIST I
(Test)
LIST II
(Observation)
A. Br2\mathrm{Br_2}Br2​ water test I. Yellow orange or orange red precipitate formed
B. Ceric ammonium nitrate test II. Reddish orange colour disappears
C. Ferric chloride test III. Red colour appears
D. 2, 4 - DNP test IV. Blue, Green, Violet or Red colour appear

Choose the correct answer from the options given below:

  1. A
    A-II, B-III, C-IV, D-I
  2. B
    A-III, B-IV, C-I, D-II
  3. C
    A-I, B-II, C-III, D-IV
  4. D
    A-IV, B-I, C-II, D-III
View written solutionFree

Correct answer: A

  1. Identify each test and its characteristic observation

    We match the tests in List I with the observations in List II.


    A. Br2\mathrm{Br_2}Br2​ water test

    Bromine water is decolourised by unsaturation or certain activated compounds.

    So, the observation is:

    Reddish orange colour disappears\text{Reddish orange colour disappears}Reddish orange colour disappears

    Hence,

    A→IIA \to IIA→II


    B. Ceric ammonium nitrate test

    Ceric ammonium nitrate test is used for alcohols. Alcohols give a red colour with ceric ammonium nitrate.

    Hence,

    B→IIIB \to IIIB→III


    C. Ferric chloride test

    Ferric chloride gives coloured complexes with phenols, producing colours like blue, green, violet, or red.

    Hence,

    C→IVC \to IVC→IV


    D. 2,4-DNP test

    2,42,42,4-dinitrophenylhydrazine reacts with aldehydes and ketones to form a yellow-orange or orange-red precipitate.

    Hence,

    D→ID \to ID→I

  2. Final matching

    Therefore, the correct matching is:

    A−II,  B−III,  C−IV,  D−IA-II,\; B-III,\; C-IV,\; D-IA−II,B−III,C−IV,D−I

  3. Compare with options

    This corresponds to Option A.

  4. Comparison with stored correct answer

    Stored correct answer = A

    Derived answer = A

    So, they agree.

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