1. Decode the IUPAC temporary name

   The systematic temporary IUPAC naming uses roots for digits:

   • $1 \to$ un
   • $0 \to$ nil
   • $2 \to$ bi
   • $3 \to$ tri
   • etc.

   The name Unununnium is formed as:

   $\text{un} + \text{un} + \text{un} + \text{ium}$

   So the atomic number is:

   $111$

2. Identify the element with atomic number 111

   Atomic number $111$ corresponds to element 111 (now named Roentgenium, Rg).

3. Find its group in the periodic table

   Element $Z=111$ lies below Cu, Ag, and Au in the d-block family:

   $\text{Cu} \,(29),\ \text{Ag} \,(47),\ \text{Au} \,(79),\ \text{Rg} \,(111)$

   These elements belong to Group 11.

4. Hence

   $n = 11$

Comparison with stored answer:

Stored correct answer = $11$

My derived answer also = $11$. So they agree.