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Periodic Table and Periodicity question

2023 · 6 Apr · Shift 2 · Q8
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Periodic Table and Periodicity question

2023 · 6 Apr · Shift 2 · Q8

JEE MainChemistryPeriodic Table and PeriodicityMCQ+4 / −1
Group-13 elements react with O2\mathrm{O}_{2}O2​ in amorphous form to form oxides of type M2O3 (M=\mathrm{M}_{2} \mathrm{O}_{3}~(\mathrm{M}=M2​O3​ (M= element). Which among the following is the most basic oxide?
  1. A
    Al 2_22​ O 3_33​
  2. B
    TI 2_22​ O 3_33​
  3. C
    B 2_22​ O 3_33​
  4. D
    Ga 2_22​ O 3_33​
View written solutionFree

Correct answer: B

  1. Identify the oxides of Group 13 elements

    The given oxides are:

    • B2O3\mathrm{B_2O_3}B2​O3​
    • Al2O3\mathrm{Al_2O_3}Al2​O3​
    • Ga2O3\mathrm{Ga_2O_3}Ga2​O3​
    • Tl2O3\mathrm{Tl_2O_3}Tl2​O3​
  2. Recall the trend in Group 13

    As we move down Group 13, the metallic character generally increases.

    • Boron is a non-metal, so B2O3\mathrm{B_2O_3}B2​O3​ is acidic.
    • Aluminium oxide Al2O3\mathrm{Al_2O_3}Al2​O3​ is amphoteric.
    • Gallium oxide Ga2O3\mathrm{Ga_2O_3}Ga2​O3​ is also amphoteric, but a bit more basic than Al2O3\mathrm{Al_2O_3}Al2​O3​.
    • Thallium is the most metallic among these, so its oxide shows the greatest basic character.
  3. Reason using metallic character and oxide nature

    In general:

    • Non-metal oxides are acidic.
    • Metal oxides are basic.
    • As metallic character increases, basic character of oxides increases.

    Therefore, the order of basicity is approximately:

    B2O3<Al2O3<Ga2O3<Tl2O3\mathrm{B_2O_3 < Al_2O_3 < Ga_2O_3 < Tl_2O_3}B2​O3​<Al2​O3​<Ga2​O3​<Tl2​O3​
  4. Evaluate the options

    • A: Al2O3\mathrm{Al_2O_3}Al2​O3​ → amphoteric, not most basic
    • B: Tl2O3\mathrm{Tl_2O_3}Tl2​O3​ → most basic
    • C: B2O3\mathrm{B_2O_3}B2​O3​ → acidic
    • D: Ga2O3\mathrm{Ga_2O_3}Ga2​O3​ → amphoteric/basic but less basic than thallium oxide
  5. Final answer

    The most basic oxide is:

    Tl2O3\boxed{\mathrm{Tl_2O_3}}Tl2​O3​​
  6. Comparison with stored correct answer

    Stored correct answer: B

    Our derived answer is also B.

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