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Periodic Table and Periodicity question

2023 · 30 Jan · Shift 1 · Q12
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Periodic Table and Periodicity question

2023 · 30 Jan · Shift 1 · Q12

JEE MainChemistryPeriodic Table and PeriodicityMCQ+4 / −1

Match List I with List II

List I
(Atomic number)		 List II
(Block of periodic table)
A. 37 I. p-block
B. 78 II. d-block
C. 52 III. f-block
D. 65 IV. s-block

Choose the correct answer from the options given below :

  1. A
    A - II, B - IV, C - I, D - III
  2. B
    A - IV, B - III, C - II, D - I
  3. C
    A - IV, B - II, C - I, D - III
  4. D
    A - I, B - III, C - IV, D - II
View written solutionFree

Correct answer: C

  1. We identify the elements from their atomic numbers and then determine their block in the periodic table.

  2. For each atomic number:

    A. Z=37Z=37Z=37

    • Element: Rubidium (Rb)(\mathrm{Rb})(Rb)
    • Electronic configuration: [Kr] 5s1[\mathrm{Kr}]\,5s^1[Kr]5s1
    • Last electron enters the sss-subshell.
    • Hence, it belongs to the sss-block.

    So, A→IVA \to IVA→IV.

    B. Z=78Z=78Z=78

    • Element: Platinum (Pt)(\mathrm{Pt})(Pt)
    • It is a transition element.
    • Transition elements belong to the ddd-block.

    So, B→IIB \to IIB→II.

    C. Z=52Z=52Z=52

    • Element: Tellurium (Te)(\mathrm{Te})(Te)
    • Electronic configuration: [Kr] 4d105s25p4[\mathrm{Kr}]\,4d^{10}5s^25p^4[Kr]4d105s25p4
    • Last electron enters the ppp-subshell.
    • Hence, it belongs to the ppp-block.

    So, C→IC \to IC→I.

    D. Z=65Z=65Z=65

    • Element: Terbium (Tb)(\mathrm{Tb})(Tb)
    • It is a lanthanide.
    • Lanthanides belong to the fff-block.

    So, D→IIID \to IIID→III.

  3. Therefore, the correct matching is:

A−IV,  B−II,  C−I,  D−IIIA-IV,\; B-II,\; C-I,\; D-IIIA−IV,B−II,C−I,D−III

  1. Now compare with the given options:
  • Option C: A−IV,B−II,C−I,D−IIIA-IV, B-II, C-I, D-IIIA−IV,B−II,C−I,D−III ✔️

Hence, the correct answer is Option C.

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