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Ionic Equilibrium question

2023 · 13 Apr · Shift 2 · Q20
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  5. /2023 · 13 Apr · Shift 2 · Q20

Ionic Equilibrium question

2023 · 13 Apr · Shift 2 · Q20

JEE MainChemistryIonic EquilibriumNumerical+4 / −1
20 mL of 0.1 M NaOH0.1 ~\mathrm{M} ~\mathrm{NaOH}0.1 M NaOH is added to 50 mL50 \mathrm{~mL}50 mL of 0.1 M0.1 ~\mathrm{M}0.1 M acetic acid solution. The pH\mathrm{pH}pH of the resulting solution is ‾\underline{\hspace{2cm}}​×10−2\times 10^{-2}×10−2(Nearest integer) Given : pKa(CH3COOH)=4.76\mathrm{pKa}\left(\mathrm{CH}_{3} \mathrm{COOH}\right)=4.76pKa(CH3​COOH)=4.76 log⁡2=0.30log⁡3=0.48\log 2=0.30\log 3=0.48log2=0.30log3=0.48
Numerical answer
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