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Ionic Equilibrium question

2023 · 25 Jan · Shift 2 · Q2
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  5. /2023 · 25 Jan · Shift 2 · Q2

Ionic Equilibrium question

2023 · 25 Jan · Shift 2 · Q2

JEE MainChemistryIonic EquilibriumMCQ+4 / −1
When the hydrogen ion concentration [H +^++] changes by a factor of 1000, the value of pH of the solution ‾\underline{\hspace{2cm}}​
  1. A
    decreases by 2 units
  2. B
    increases by 2 units
  3. C
    decreases by 3 units
  4. D
    increases by 1000 units
View written solutionFree

Correct answer: C

  1. Use the definition of pH

    pH=−log⁡10[H+]\text{pH} = -\log_{10}[H^+]pH=−log10​[H+]

  2. Let the initial hydrogen ion concentration be

    [H+]=x[H^+] = x[H+]=x

    Then initial pH is

    pH1=−log⁡x\text{pH}_1 = -\log xpH1​=−logx

  3. If [H+][H^+][H+] changes by a factor of 1000

    Since pH is inversely related to [H+][H^+][H+], take the common interpretation that hydrogen ion concentration increases by a factor of 1000=1031000 = 10^31000=103.

    So new concentration is

    [H+]2=1000x=103x[H^+]_2 = 1000x = 10^3x[H+]2​=1000x=103x

  4. Find the new pH

    pH2=−log⁡(103x)\text{pH}_2 = -\log(10^3x)pH2​=−log(103x)

    pH2=−(log⁡x+3)\text{pH}_2 = -\left(\log x + 3\right)pH2​=−(logx+3)

    pH2=−log⁡x−3\text{pH}_2 = -\log x - 3pH2​=−logx−3

    pH2=pH1−3\text{pH}_2 = \text{pH}_1 - 3pH2​=pH1​−3

  5. Interpret the result

    The pH becomes smaller by 3 units.

    So, the pH decreases by 3 units.

  6. Check options

    • A: decreases by 2 units — incorrect
    • B: increases by 2 units — incorrect
    • C: decreases by 3 units — correct
    • D: increases by 1000 units — incorrect

Final Answer: Option C.

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