Sign in
12thPass logo
New chatPYQ LibraryDoubtsRank report
Sign in to see Recents

Your guest activity stays on this device

Sign in to save progress →
Sign in

Ionic Equilibrium question

2023 · 31 Jan · Shift 2 · Q13
Guest · filters and generic practice availableBrowsing as a guest · PYQ filters and generic practice are available. Sign in only for personalised features and saved progress.
  1. PYQ Library
  2. /JEE Main
  3. /Chemistry
  4. /Ionic Equilibrium
  5. /2023 · 31 Jan · Shift 2 · Q13

Ionic Equilibrium question

2023 · 31 Jan · Shift 2 · Q13

JEE MainChemistryIonic EquilibriumMCQ+4 / −1
The incorrect statement for the use of indicators in acid-base titration is :
  1. A
    Phenolphthalein is a suitable indicator for a weak acid vs strong base titration.
  2. B
    Methyl orange may be used for a weak acid vs weak base titration.
  3. C
    Methyl orange is a suitable indicator for a strong acid vs weak base titration.
  4. D
    Phenolphthalein may be used for a strong acid vs strong base titration.
View written solutionFree

Correct answer: B

  1. Principle of indicator selection

    In acid-base titration, the indicator must change colour in the steep pH jump region near the equivalence point.

    Common indicator ranges:

    • Methyl orange: pH 3.1−4.4\text{pH } 3.1 - 4.4pH 3.1−4.4
    • Phenolphthalein: pH 8.3−10.0\text{pH } 8.3 - 10.0pH 8.3−10.0
  2. Examine each titration type

    (A) Weak acid vs strong base

    At equivalence point, solution is basic (pH>7\text{pH} > 7pH>7). So an indicator changing in alkaline range is suitable.

    • Phenolphthalein changes in 8.3−10.08.3-10.08.3−10.0
    • Hence, it is suitable.

    Therefore, A is correct.

    (B) Weak acid vs weak base

    For weak acid vs weak base titration, the pH change near equivalence point is not sharp. So no common visual indicator gives a reliable end point.

    Therefore, methyl orange should not be used.

    Hence, B is incorrect.

    (C) Strong acid vs weak base

    At equivalence point, solution is acidic (pH<7\text{pH} < 7pH<7). So an indicator with acidic transition range is suitable.

    • Methyl orange changes in 3.1−4.43.1-4.43.1−4.4
    • This matches the steep region reasonably well.

    Therefore, C is correct.

    (D) Strong acid vs strong base

    At equivalence point, pH≈7\text{pH} \approx 7pH≈7, but the pH jump is very steep and wide. So both methyl orange and phenolphthalein can generally be used.

    Therefore, D is correct.

  3. Conclusion

    The incorrect statement is: B\boxed{\text{B}}B​

  4. Comparison with stored answer

    Stored correct answer = B

    My derived answer = B

    So, they agree.

PreviousNext

More from Ionic Equilibrium

  • At 298 K, the solubility of silver chloride in water is 1.434×10−3 g L−1. The value of −logKsp​ for silver chloride is ​. (Given mass of Ag…2023 · Numerical
  • 20 mL of 0.1MNH4​OH is mixed with 40 mL of 0.05MHCl. The pH of the mixture is nearest to : (Given : Kb​(NH4​OH)=1×10−5,log2=0.30,log3=0.48,log5=0.69,log7=0.84,log11=1.04)…2022 · MCQ
  • Ka1​​, Ka2​​ and Ka3​​ are the respective ionization constants for the following reactions (a), (b) and (c). (a) H2​C2​O4​⇌H++HC2​O4−​(b) HC2​O4−​⇌H++C2​O42−​…2022 · MCQ
  • The Ksp for bismuth sulphide (Bi2​S3​) is 1.08 × 10 − 73. The solubility of Bi2​S3​ in mol L − 1 at 298 K is :2022 · MCQ
  • Given below are two statements one is labelled as Assertion A and the other is labelled as Reason R : Assertion A : The amphoteric nature of water is explained by using Lewis acid/base concept. Reason R : Water acts as an acid with NH3​…2022 · MCQ
  • Class XII students were asked to prepare one litre of buffer solution of pH8.26 by their Chemistry teacher: The amount of ammonium chloride to be dissolved by the student in 0.2M ammonia solution to make one…2022 · MCQ
  • 50 mL of 0.1 M CH3​COOH is being titrated against 0.1 M NaOH. When 25 mL of NaOH has been added, the pH of the solution will be ​× 10 − 2. (Nearest integer) (Given : pKa (CH3​COOH) = 4.76) log 2 =…2022 · Numerical
  • At 310 K, the solubility of CaF2​ in water is 2.34×10−3 g/100 mL. The solubility product of CaF2​ is ​×10−8( mol/L)3…2022 · Numerical