Identify the compound

1-methyl ethylene oxide is the epoxide propylene oxide (also called 1,2-epoxypropane): $\ce{CH3-CH-CH2}$ with an oxygen bridging the last two carbons.

Reaction of epoxide with HBr

Epoxides react with hydrogen halides by:

• protonation of the oxygen,
• followed by ring opening by bromide ion.

First, one mole of HBr opens the epoxide ring to give a bromo alcohol.

For propylene oxide, the product is: $\ce{CH3-CH(OH)-CH2Br}$ or equivalently under acidic conditions, ring opening gives the bromohydrin.

Effect of excess HBr

Since HBr is in excess, the alcohol group is further replaced by bromine.

Thus: $\ce{CH3-CH(OH)-CH2Br + HBr -> CH3-CHBr-CH2Br + H2O}$

Final product

Therefore, the final product is: $\ce{CH3-CHBr-CH2Br}$

This is 1,2-dibromopropane.

Conclusion

So, 1-methyl ethylene oxide with excess HBr gives 1,2-dibromopropane.

Comparison with stored answer

The stored correct answer is A. Since the option texts are not visible, I infer that A corresponds to 1,2-dibromopropane.

Hence, I agree with the stored answer provided option A is 1,2-dibromopropane.