Use Faraday’s law of electrolysis

One Faraday of charge deposits one gram-equivalent of a substance.

For copper deposition from copper sulphate

Copper is deposited as: $\text{Cu}^{2+} + 2e^- \rightarrow \text{Cu}$

So, copper requires $2$ moles of electrons per mole of Cu.

Amount deposited by 1 Faraday

Since $1$ Faraday $= 1$ mole of electrons, the amount of copper deposited is: $\frac{1}{2} \text{ mole of Cu}$

Now, $1$ gram-atom of copper $= 1$ mole of copper. Hence, deposited copper $= 0.5$ gram-atom.

Match with the given form

Given: $x \times 10^{-1} = 0.5$

$x \times 0.1 = 0.5$

$x = 5$

Final answer

$\boxed{5}$

Comparison with stored correct answer

Stored correct answer = $5$

This matches the derived answer.