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Electrochemistry question

2023 · 8 Apr · Shift 2 · Q21
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Electrochemistry question

2023 · 8 Apr · Shift 2 · Q21

JEE MainChemistryElectrochemistryNumerical+4 / −1
The number of incorrect statements from the following is ‾\underline{\hspace{2cm}}​. A. The electrical work that a reaction can perform at constant pressure and temperature is equal to the reaction Gibbs energy. B. Ecell∘\mathrm{E_{cell}^{\circ}}Ecell∘​ cell is dependent on the pressure. C. dEθ cell dT=ΔrSθnF\frac{d E^{\theta} \text { cell }}{\mathrm{dT}}=\frac{\Delta_{\mathrm{r}} \mathrm{S}^{\theta}}{\mathrm{nF}}dTdEθ cell ​=nFΔr​Sθ​ D. A cell is operating reversibly if the cell potential is exactly balanced by an opposing source of potential difference.
Numerical answer
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Correct answer: 1

  1. Statement A: “The electrical work that a reaction can perform at constant pressure and temperature is equal to the reaction Gibbs energy.”

    For a galvanic cell operating reversibly at constant temperature and pressure, ΔG=−nFEcell\Delta G = -nFE_{\text{cell}}ΔG=−nFEcell​ and the maximum electrical work is welec,max=−ΔGw_{\text{elec,max}} = -\Delta Gwelec,max​=−ΔG So the magnitude of electrical work equals the decrease in Gibbs energy, but it is not equal to ΔG\Delta GΔG directly because of sign convention.

    Hence, Statement A is incorrect.

  2. Statement B: “Ecell∘E_{\text{cell}}^{\circ}Ecell∘​ is dependent on the pressure.”

    Standard cell potential is related to standard Gibbs energy: ΔG∘=−nFEcell∘\Delta G^{\circ} = -nF E_{\text{cell}}^{\circ}ΔG∘=−nFEcell∘​ Since standard Gibbs energy depends on temperature and on the defined standard states, and for gases the standard state involves pressure, Ecell∘E_{\text{cell}}^{\circ}Ecell∘​ can depend on pressure.

    Hence, Statement B is correct.

  3. Statement C: dEcellθdT=ΔrSθnF\frac{dE_{\text{cell}}^{\theta}}{dT} = \frac{\Delta_r S^{\theta}}{nF}dTdEcellθ​​=nFΔr​Sθ​

    We use ΔG∘=−nFEcell∘\Delta G^{\circ} = -nF E_{\text{cell}}^{\circ}ΔG∘=−nFEcell∘​ Differentiate w.r.t. TTT: d(ΔG∘)dT=−nFdEcell∘dT\frac{d(\Delta G^{\circ})}{dT} = -nF\frac{dE_{\text{cell}}^{\circ}}{dT}dTd(ΔG∘)​=−nFdTdEcell∘​​ But, (dGdT)P=−S⇒d(ΔG∘)dT=−ΔrS∘\left(\frac{dG}{dT}\right)_P = -S \Rightarrow \frac{d(\Delta G^{\circ})}{dT} = -\Delta_r S^{\circ}(dTdG​)P​=−S⇒dTd(ΔG∘)​=−Δr​S∘ Therefore, −ΔrS∘=−nFdEcell∘dT-\Delta_r S^{\circ} = -nF\frac{dE_{\text{cell}}^{\circ}}{dT}−Δr​S∘=−nFdTdEcell∘​​ dEcell∘dT=ΔrS∘nF\frac{dE_{\text{cell}}^{\circ}}{dT} = \frac{\Delta_r S^{\circ}}{nF}dTdEcell∘​​=nFΔr​S∘​

    Hence, Statement C is correct.

  4. Statement D: “A cell is operating reversibly if the cell potential is exactly balanced by an opposing source of potential difference.”

    This is the condition of reversible operation: when the opposing potential is equal to the cell emf, current tends to zero and the process is reversible.

    Hence, Statement D is correct.

  5. Counting incorrect statements

    • A: Incorrect
    • B: Correct
    • C: Correct
    • D: Correct

    Therefore, the number of incorrect statements = 1.

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