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Electrochemistry question

2023 · 1 Feb · Shift 1 · Q14

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JEE Main
Chemistry
Electrochemistry
2023 · 1 Feb · Shift 1 · Q14

Electrochemistry question

2023 · 1 Feb · Shift 1 · Q14

JEE MainChemistryElectrochemistryNumerical+4 / −1

At what pH, given half cell

\mathrm{MnO_{4}^{-}(0.1~M)~|~Mn^{2+}(0.001~M)}

will have electrode potential of 1.282 V?

\underline{\hspace{2cm}}

(Nearest Integer) Given

\mathrm{E_{MnO_4^ - |M{n^{2 + }}}^o}=1.54~\mathrm{V},\frac{2.303\mathrm{RT}}{\mathrm{F}}=0.059\mathrm{V}

Numerical answer

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