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Electrochemistry question

2023 · 10 Apr · Shift 2 · Q20
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  5. /2023 · 10 Apr · Shift 2 · Q20

Electrochemistry question

2023 · 10 Apr · Shift 2 · Q20

JEE MainChemistryElectrochemistryNumerical+4 / −1
The specific conductance of 0.0025 M0.0025 ~\mathrm{M}0.0025 M acetic acid is 5×10−5 S cm−15 \times 10^{-5} \mathrm{~S} \mathrm{~cm}^{-1}5×10−5 S cm−1 at a certain temperature. The dissociation constant of acetic acid is ‾\underline{\hspace{2cm}}​× 10−7\times ~10^{-7}× 10−7(Nearest integer) Consider limiting molar conductivity of CH3COOH\mathrm{CH}_{3} \mathrm{COOH}CH3​COOH as 400 S cm2 mol−1400 \mathrm{~S} \mathrm{~cm}^{2} \mathrm{~mol}^{-1}400 S cm2 mol−1
Numerical answer
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