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Electrochemistry question

2023 · 13 Apr · Shift 2 · Q19
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Electrochemistry question

2023 · 13 Apr · Shift 2 · Q19

JEE MainChemistryElectrochemistryNumerical+4 / −1
At 298 K298 \mathrm{~K}298 K, the standard reduction potential for Cu2+/Cu\mathrm{Cu}^{2+} / \mathrm{Cu}Cu2+/Cu electrode is 0.34 V0.34 \mathrm{~V}0.34 V. Given : KspCu(OH)2=1×10−20\mathrm{K}_{\mathrm{sp}} \mathrm{Cu}(\mathrm{OH})_{2}=1 \times 10^{-20}Ksp​Cu(OH)2​=1×10−20 Take 2.303RTF=0.059 V\frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.059 \mathrm{~V}F2.303RT​=0.059 V The reduction potential at pH=14\mathrm{pH}=14pH=14 for the above couple is (−)x×10−2 V(-) x \times 10^{-2} \mathrm{~V}(−)x×10−2 V. The value of xxx is ‾\underline{\hspace{2cm}}​
Numerical answer
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