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Electrochemistry question

2023 · 11 Apr · Shift 1 · Q24

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JEE Main
Chemistry
Electrochemistry
2023 · 11 Apr · Shift 1 · Q24

Electrochemistry question

2023 · 11 Apr · Shift 1 · Q24

JEE MainChemistryElectrochemistryNumerical+4 / −1

In an electrochemical reaction of lead, at standard temperature, if

\mathrm{E}^{0}\left(\mathrm{~Pb}^{2+} / \mathrm{Pb}\right)=\mathrm{m}

Volt and

\mathrm{E}^{0}\left(\mathrm{~Pb}^{4+} / \mathrm{Pb}\right)=\mathrm{n}

Volt, then the value of

\mathrm{E}^{0}\left(\mathrm{~Pb}^{2+} / \mathrm{Pb}^{4+}\right)

is given by

\mathrm{m-x n}

. The value of

\mathrm{x}

is

\underline{\hspace{2cm}}

. (Nearest integer)

Numerical answer

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