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Electrochemistry question

2020 · 6 Sep · Shift 1 · Q3

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JEE Main
Chemistry
Electrochemistry
2020 · 6 Sep · Shift 1 · Q3

Electrochemistry question

2020 · 6 Sep · Shift 1 · Q3

JEE MainChemistryElectrochemistryNumerical+4 / −1

Potassium chlorate is prepared by the electrolysis of

KCl

in basic solution

6OH^- + Cl^-

\to

ClO_3^- + 3H_2O + 6e^-

If only 60% of the current is utilized in the reaction, the time (rounded to the nearest hour) required to produce 10 g of

KClO_3

using a current of 2 A is

\underline{\hspace{2cm}}

. (Given : F = 96,500 C mol–1; molar mass of

KCIO_3

= 122 g mol–1)

Numerical answer

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