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D and F Block Elements question

2022 · 27 Jun · Shift 1 · Q16
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D and F Block Elements question

2022 · 27 Jun · Shift 1 · Q16

JEE MainChemistryD and F Block ElementsNumerical+4 / −1
The number of statements correct from the following for Copper (at. no. 29) is/are ‾\underline{\hspace{2cm}}​. (A) Cu(II) complexes are always paramagnetic. (B) Cu(I) complexes are generally colourless (C) Cu(I) is easily oxidized (D) In Fehling solution, the active reagent has Cu(I)
Numerical answer
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Correct answer: 3

  1. Electronic configurations of copper ions

Copper has atomic number 292929.

Its ground-state electronic configuration is:

Cu:[Ar] 3d104s1\mathrm{Cu}: [Ar] \, 3d^{10}4s^1Cu:[Ar]3d104s1

So,

  • Cu+\mathrm{Cu}^+Cu+ : [Ar] 3d10[Ar] \, 3d^{10}[Ar]3d10
  • Cu2+\mathrm{Cu}^{2+}Cu2+ : [Ar] 3d9[Ar] \, 3d^9[Ar]3d9

  1. Check statement (A): Cu(II) complexes are always paramagnetic

Cu2+\mathrm{Cu}^{2+}Cu2+ has configuration 3d93d^93d9. A d9d^9d9 system has one unpaired electron, so Cu(II) complexes are paramagnetic.

Thus, statement (A) is correct.


  1. Check statement (B): Cu(I) complexes are generally colourless

Cu+\mathrm{Cu}^+Cu+ has configuration 3d103d^{10}3d10. Since the ddd-subshell is completely filled, ddd-ddd transitions are not possible. Therefore, Cu(I) compounds/complexes are generally colourless.

Thus, statement (B) is correct.


  1. Check statement (C): Cu(I) is easily oxidized

Cu+\mathrm{Cu}^+Cu+ can be oxidized to Cu2+\mathrm{Cu}^{2+}Cu2+, but in aqueous chemistry it is more known to be unstable and undergo disproportionation:

2Cu+→Cu2++Cu2\mathrm{Cu}^+ \rightarrow \mathrm{Cu}^{2+} + \mathrm{Cu}2Cu+→Cu2++Cu

However, compared with Cu(II), Cu(I) is indeed readily converted to Cu(II) because Cu2+\mathrm{Cu}^{2+}Cu2+ is more stable in aqueous medium. So the statement that Cu(I) is easily oxidized is taken as correct in standard inorganic chemistry context.

Thus, statement (C) is correct.


  1. Check statement (D): In Fehling solution, the active reagent has Cu(I)

Fehling solution contains a Cu(II)-tartrate complex in alkaline medium. During reaction with aldehydes/reducing sugars, Cu(II) is reduced to Cu(I) oxide (Cu2O\mathrm{Cu_2O}Cu2​O), the red precipitate.

So the active reagent initially contains Cu(II), not Cu(I).

Thus, statement (D) is incorrect.


  1. Count correct statements

Correct statements are:

  • (A) Correct
  • (B) Correct
  • (C) Correct
  • (D) Incorrect

Hence, the number of correct statements is:

333
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