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D and F Block Elements question

2014 · Shift 0 · Q19
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D and F Block Elements question

2014 · Shift 0 · Q19

JEE MainChemistryD and F Block ElementsMCQ+4 / −1
Which series of reactions correctly represents chemical relations related to iron and its compound?
  1. A
    FeFeFe →dil. H2SO4\xrightarrow{dil.\,{H_2}S{O_4}}dil.H2​SO4​​ FeSO4FeSO_4FeSO4​ →H2SO4,O2\xrightarrow{{H_2}S{O_4},{O_2}}H2​SO4​,O2​​ Fe2(SO4)3Fe_2(SO_4)_3Fe2​(SO4​)3​ →heat\xrightarrow{heat}heat​ FeFeFe
  2. B
    FeFeFe →O2 ,heat\xrightarrow{{O_2} \, {, heat}}O2​,heat​ FeOFeOFeO →dil. H2SO4\xrightarrow{dil.\,{H_2}S{O_4}}dil.H2​SO4​​ FeSO4FeSO_4FeSO4​ →heat\xrightarrow{heat}heat​ FeFeFe
  3. C
    FeFeFe →Cl2 ,heat\xrightarrow{{Cl_2} \, {, heat}}Cl2​,heat​ FeCl3FeCl_3FeCl3​ →heat, air\xrightarrow{heat, \, air}heat,air​ FeCl2FeCl_2FeCl2​ →Zn\xrightarrow{Zn}Zn​ FeFeFe
  4. D
    FeFeFe →O2, heat\xrightarrow{{O_2},\,heat}O2​,heat​ Fe3O4Fe_3O_4Fe3​O4​ →CO, 600oC\xrightarrow{CO,\,{{600}^o}C}CO,600oC​ FeOFeOFeO →CO, 700oC\xrightarrow{CO,\,{{700}^o}C}CO,700oC​ FeFeFe
View written solutionFree

Correct answer: D

  1. Check option A

    Fe→dil. H2SO4FeSO4Fe \xrightarrow{dil.\,H_2SO_4} FeSO_4Fedil.H2​SO4​​FeSO4​ This is correct: Fe+H2SO4(dil.)→FeSO4+H2Fe + H_2SO_4(dil.) \rightarrow FeSO_4 + H_2Fe+H2​SO4​(dil.)→FeSO4​+H2​

    Next: FeSO4→H2SO4, O2Fe2(SO4)3FeSO_4 \xrightarrow{H_2SO_4,\,O_2} Fe_2(SO_4)_3FeSO4​H2​SO4​,O2​​Fe2​(SO4​)3​ Ferrous sulfate can be oxidized to ferric sulfate in acidic medium, so this step is acceptable.

    Last step: Fe2(SO4)3→heatFeFe_2(SO_4)_3 \xrightarrow{heat} FeFe2​(SO4​)3​heat​Fe This is wrong. On heating, ferric sulfate does not directly give iron metal. It decomposes to ferric oxide and sulfur oxides: Fe2(SO4)3→ΔFe2O3+3SO3Fe_2(SO_4)_3 \xrightarrow{\Delta} Fe_2O_3 + 3SO_3Fe2​(SO4​)3​Δ​Fe2​O3​+3SO3​ Hence, A is incorrect.

  2. Check option B

    Fe→O2, heatFeOFe \xrightarrow{O_2,\,heat} FeOFeO2​,heat​FeO This is not the usual direct oxidation product of iron in air/oxygen. Iron generally forms: Fe3O4 or Fe2O3Fe_3O_4 \text{ or } Fe_2O_3Fe3​O4​ or Fe2​O3​ not pure FeOFeOFeO directly.

    Also: FeSO4→heatFeFeSO_4 \xrightarrow{heat} FeFeSO4​heat​Fe is again wrong. On heating: 2FeSO4→ΔFe2O3+SO2+SO32FeSO_4 \xrightarrow{\Delta} Fe_2O_3 + SO_2 + SO_32FeSO4​Δ​Fe2​O3​+SO2​+SO3​ So B is incorrect.

  3. Check option C

    Fe→Cl2, heatFeCl3Fe \xrightarrow{Cl_2,\,heat} FeCl_3FeCl2​,heat​FeCl3​ This is correct.

    Next: FeCl3→heat, airFeCl2FeCl_3 \xrightarrow{heat,\,air} FeCl_2FeCl3​heat,air​FeCl2​ This is wrong. Air would favor oxidation, not reduction. FeCl3FeCl_3FeCl3​ does not convert to FeCl2FeCl_2FeCl2​ by heating in air.

    Though: FeCl2→ZnFeFeCl_2 \xrightarrow{Zn} FeFeCl2​Zn​Fe is possible since zinc is more reactive, the middle step is invalid.

    Hence, C is incorrect.

  4. Check option D

    Fe→O2, heatFe3O4Fe \xrightarrow{O_2,\,heat} Fe_3O_4FeO2​,heat​Fe3​O4​ This is correct. Iron on heating in oxygen forms magnetite: 3Fe+2O2→Fe3O43Fe + 2O_2 \rightarrow Fe_3O_43Fe+2O2​→Fe3​O4​

    Next: Fe3O4→CO, 600∘CFeOFe_3O_4 \xrightarrow{CO,\,600^\circ C} FeOFe3​O4​CO,600∘C​FeO This is consistent with stepwise reduction of iron oxides by CO.

    Then: FeO→CO, 700∘CFeFeO \xrightarrow{CO,\,700^\circ C} FeFeOCO,700∘C​Fe This is also correct: FeO+CO→Fe+CO2FeO + CO \rightarrow Fe + CO_2FeO+CO→Fe+CO2​

    Thus, D is correct.

  5. Final conclusion

    The correctly represented series is: D\boxed{D}D​

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