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Coordination Compounds question

2023 · 11 Apr · Shift 2 · Q7
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Coordination Compounds question

2023 · 11 Apr · Shift 2 · Q7

JEE MainChemistryCoordination CompoundsMCQ+4 / −1

Match List I with List II

LIST I
Complex		 LIST II
Colour
A. Mg(NH4)PO4Mg(N{H_4})P{O_4}Mg(NH4​)PO4​ I. brown
B. K3[Co(NO2)6]{K_3}[Co{(N{O_2})_6}]K3​[Co(NO2​)6​] II. white
C. MnO(OH)2MnO{(OH)_2}MnO(OH)2​ III. yellow
D. Fe4[Fe(CN)6]3F{e_4}{[Fe{(CN)_6}]_3}Fe4​[Fe(CN)6​]3​ IV. blue

Choose the correct answer from the options given below :

  1. A
    A-II, B-IV, C-I, D-III
  2. B
    A-II, B-III, C-I, D-IV
  3. C
    A-III, B-IV, C-II, D-I
  4. D
    A-II, B-III, C-IV, D-I
View written solutionFree

Correct answer: B

  1. We identify the characteristic colours of each compound in List I.
  1. Compound A: Mg(NH4)PO4Mg(NH_4)PO_4Mg(NH4​)PO4​

This is magnesium ammonium phosphate, which is a white precipitate.

So, A→II (white)A \to \text{II (white)}A→II (white)

  1. Compound B: K3[Co(NO2)6]K_3[Co(NO_2)_6]K3​[Co(NO2​)6​]

This is potassium cobaltinitrite. It is known to be yellow in colour.

So, B→III (yellow)B \to \text{III (yellow)}B→III (yellow)

  1. Compound C: MnO(OH)2MnO(OH)_2MnO(OH)2​

This corresponds to a hydrated/mixed oxide-hydroxide manganese compound, known to give a brown colour/precipitate.

So, C→I (brown)C \to \text{I (brown)}C→I (brown)

  1. Compound D: Fe4[Fe(CN)6]3Fe_4[Fe(CN)_6]_3Fe4​[Fe(CN)6​]3​

This is Prussian blue (ferric ferrocyanide), which is characteristically blue.

So, D→IV (blue)D \to \text{IV (blue)}D→IV (blue)

  1. Therefore, the correct matching is:

A−II,B−III,C−I,D−IVA-\text{II},\quad B-\text{III},\quad C-\text{I},\quad D-\text{IV}A−II,B−III,C−I,D−IV

This corresponds to Option B.

  1. Comparison with stored correct answer

Stored correct answer = B

Our derived answer = B

Hence, they agree.

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