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Coordination Compounds question

2021 · 27 Aug · Shift 2 · Q14
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  5. /2021 · 27 Aug · Shift 2 · Q14

Coordination Compounds question

2021 · 27 Aug · Shift 2 · Q14

JEE MainChemistryCoordination CompoundsNumerical+4 / −1
The number of optical isomers possible for [Cr(C2O4)3]3−[Cr(C_2O_4)_3]^{3-}[Cr(C2​O4​)3​]3− is ‾\underline{\hspace{2cm}}​.
Numerical answer
View written solutionFree

Correct answer: 2

  1. Identify the complex geometry

The complex is [Cr(C2O4)3]3−[Cr(C_2O_4)_3]^{3-}[Cr(C2​O4​)3​]3− Here, Cr3+Cr^{3+}Cr3+ is coordinated by three oxalate ligands.

  • Oxalate, C2O42−C_2O_4^{2-}C2​O42−​, is a bidentate ligand.
  • Three bidentate ligands occupy 666 coordination sites.

So the complex has octahedral geometry.


  1. Nature of the ligand arrangement

For an octahedral complex of the type [M(AA)3][M(AA)_3][M(AA)3​] where AAAAAA is a symmetrical bidentate ligand, the complex can show optical isomerism.

This happens because the three chelate rings can wrap around the metal center in two non-superimposable mirror-image forms:

  • Δ\DeltaΔ form
  • Λ\LambdaΛ form

These are enantiomers.


  1. Count the optical isomers

Since there are only these two mirror-image forms, the number of optical isomers is 222


  1. Final answer

2\boxed{2}2​


  1. Comparison with stored correct answer

Stored correct answer = 222

My derived answer = 222

So they agree.

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