JEE MainChemistryCoordination CompoundsMCQ+4 / −1
displays :
- Aone Co−Co bond, six terminal CO and two bridging CO
- Bone Co−Co bond, four terminal CO and four bridging CO
- Cno Co−Co bond, six terminal CO and two bridging CO
- Dno Co−Co bond, four terminal CO and four bridging CO
View written solutionFree
Correct answer: A
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We need the structure of .
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This is a well-known metal carbonyl dimer. Its usual structure contains:
- one bond
- two bridging carbonyls (-CO)
- six terminal carbonyls
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We can also check by electron counting.
For each Co atom:
- Cobalt is in group 9, so it contributes electrons.
- In the bridged dimer form, each Co is bonded to:
- terminal CO ligands electrons
- bridging CO ligands, each contributing electron to a given Co in neutral counting electrons
- one bond electron to each Co
Total per Co:
So the structure satisfies the -electron rule.
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Now evaluate the options:
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A: one bond, six terminal CO and two bridging CO
This matches the known structure. -
B: one bond, four terminal CO and four bridging CO
Not the accepted structure for . -
C: no bond, six terminal CO and two bridging CO
Incorrect, because the dimer has a bond. -
D: no bond, four terminal CO and four bridging CO
Incorrect.
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-
Therefore, the correct option is:
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Comparison with stored correct answer:
- Stored correct answer: A
- Derived answer: A
- They agree.
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