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Coordination Compounds question

2017 · Shift 0 · Q11
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Coordination Compounds question

2017 · Shift 0 · Q11

JEE MainChemistryCoordination CompoundsMCQ+4 / −1
On treatment of 100 mL of 0.1 M solution of CoCl3CoCl_3CoCl3​. 6H2OH_2OH2​O with excess AgNO3AgNO_3AgNO3​; 1.2 ×\times× 1022 ions are precipitated. The complex is :
  1. A
    [Co(H2O)3Cl3][Co(H_2O)_3Cl_3][Co(H2​O)3​Cl3​].3H2OH_2OH2​O
  2. B
    [Co(H2O)6]Cl3[Co(H_2O)_6]Cl_3[Co(H2​O)6​]Cl3​
  3. C
    [Co(H2O)5Cl]Cl2[Co(H_2O)_5Cl]Cl_2[Co(H2​O)5​Cl]Cl2​.H2OH_2OH2​O
  4. D
    [Co(H2O)4Cl2]Cl[Co(H_2O)_4Cl_2]Cl[Co(H2​O)4​Cl2​]Cl.2H2OH_2OH2​O
View written solutionFree

Correct answer: C

  1. Moles of CoCl3⋅6H2OCoCl_3\cdot 6H_2OCoCl3​⋅6H2​O taken

Given:

  • Volume =100 mL=0.1 L=100\ \text{mL}=0.1\ \text{L}=100 mL=0.1 L
  • Molarity =0.1 M=0.1\ \text{M}=0.1 M

So, moles of compound are n=M×V=0.1×0.1=0.01 moln = M\times V = 0.1\times 0.1 = 0.01\ \text{mol}n=M×V=0.1×0.1=0.01 mol

  1. Number of formula units present

0.01×NA=0.01×6.022×1023=6.022×10210.01\times N_A = 0.01\times 6.022\times 10^{23} = 6.022\times 10^{21}0.01×NA​=0.01×6.022×1023=6.022×1021

  1. Chloride ions precipitated by AgNO3AgNO_3AgNO3​

Given precipitated ions: 1.2×10221.2\times 10^{22}1.2×1022

These are chloride ions precipitated as AgClAgClAgCl, so number of chloride ions liberated per formula unit is

1.2×10226.022×1021≈1.99≈2\frac{1.2\times 10^{22}}{6.022\times 10^{21}} \approx 1.99 \approx 26.022×10211.2×1022​≈1.99≈2

So, 2 chloride ions per formula unit are outside the coordination sphere.

  1. Identify the complex

We need the hydrate of CoCl3⋅6H2OCoCl_3\cdot 6H_2OCoCl3​⋅6H2​O having 2 ionisable chloride ions.

Check options:

  • A [Co(H2O)3Cl3]⋅3H2O[Co(H_2O)_3Cl_3]\cdot 3H_2O[Co(H2​O)3​Cl3​]⋅3H2​O
    Outside coordination sphere: 0 Cl−0\ Cl^-0 Cl−

  • B [Co(H2O)6]Cl3[Co(H_2O)_6]Cl_3[Co(H2​O)6​]Cl3​
    Outside coordination sphere: 3 Cl−3\ Cl^-3 Cl−

  • C [Co(H2O)5Cl]Cl2⋅H2O[Co(H_2O)_5Cl]Cl_2\cdot H_2O[Co(H2​O)5​Cl]Cl2​⋅H2​O
    Outside coordination sphere: 2 Cl−2\ Cl^-2 Cl−

  • D [Co(H2O)4Cl2]Cl⋅2H2O[Co(H_2O)_4Cl_2]Cl\cdot 2H_2O[Co(H2​O)4​Cl2​]Cl⋅2H2​O
    Outside coordination sphere: 1 Cl−1\ Cl^-1 Cl−

Hence the correct complex is [Co(H2O)5Cl]Cl2⋅H2O[Co(H_2O)_5Cl]Cl_2\cdot H_2O[Co(H2​O)5​Cl]Cl2​⋅H2​O

  1. Correct option

C\boxed{\text{C}}C​

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