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Chemical Bonding and Molecular Structure question

2025 · 7 Apr · Shift 2 · Q5
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Chemical Bonding and Molecular Structure question

2025 · 7 Apr · Shift 2 · Q5

JEE MainChemistryChemical Bonding and Molecular StructureMCQ+4 / −1
In SO2SO_2SO2​, NO2NO_2NO2​ −-− and N3N_3N3​ −-−, the hybridizations at the central atom are respectively :
  1. A
    sp2, sp2 and sp2
  2. B
    sp, sp2 and sp
  3. C
    sp2, sp and sp
  4. D
    sp2, sp2 and sp
View written solutionFree

Correct answer: D

  1. Determine hybridization using steric number
    Hybridization at the central atom is found from the number of electron domains around it:
Steric number=number of σ-bonds+number of lone pairs\text{Steric number} = \text{number of }\sigma\text{-bonds} + \text{number of lone pairs}Steric number=number of σ-bonds+number of lone pairs
  • Steric number 2⇒sp2 \Rightarrow sp2⇒sp
  • Steric number 3⇒sp23 \Rightarrow sp^23⇒sp2
  • Steric number 4⇒sp34 \Rightarrow sp^34⇒sp3
  1. For SO2SO_2SO2​
    Sulfur is the central atom.

Structure: sulfur forms two σ\sigmaσ bonds with two oxygens and has one lone pair on sulfur. So,

Steric number=2+1=3\text{Steric number} = 2 + 1 = 3Steric number=2+1=3

Hence hybridization is

sp2sp^2sp2
  1. For NO2−NO_2^-NO2−​
    Nitrogen is the central atom.

In nitrite ion, nitrogen forms two σ\sigmaσ bonds with two oxygens and has one lone pair. So,

Steric number=2+1=3\text{Steric number} = 2 + 1 = 3Steric number=2+1=3

Hence hybridization is

sp2sp^2sp2
  1. For N3−N_3^-N3−​
    This is azide ion. The central nitrogen is bonded to two terminal nitrogens.

Resonance structures are linear, and the central nitrogen has two electron domains (two σ\sigmaσ bonds, no lone pair on central N in the main description). So,

Steric number=2\text{Steric number} = 2Steric number=2

Hence hybridization is

spspsp
  1. Collect the results
SO2:sp2,NO2−:sp2,N3−:spSO_2 : sp^2, \qquad NO_2^- : sp^2, \qquad N_3^- : spSO2​:sp2,NO2−​:sp2,N3−​:sp

This matches Option D.

  1. Comparison with stored correct answer
    Stored correct answer: D
    Derived answer: D
    So, the answers agree.
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