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Chemical Bonding and Molecular Structure question

2023 · 31 Jan · Shift 2 · Q16
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Chemical Bonding and Molecular Structure question

2023 · 31 Jan · Shift 2 · Q16

JEE MainChemistryChemical Bonding and Molecular StructureNumerical+4 / −1
Amongst the following, the number of species having the linear shape is ‾\underline{\hspace{2cm}}​. XeF2,I3+,C3O2,I3−,CO2,SO2,BeCl2\mathrm{XeF}_{2}, \mathrm{I}_{3}^{+}, \mathrm{C}_{3} \mathrm{O}_{2}, \mathrm{I}_{3}^{-}, \mathrm{CO}_{2}, \mathrm{SO}_{2}, \mathrm{BeCl}_{2}XeF2​,I3+​,C3​O2​,I3−​,CO2​,SO2​,BeCl2​ and BCl2⊖\mathrm{BCl}_{2}^{\ominus}BCl2⊖​
Numerical answer
View written solutionFree

Correct answer: 5

  1. We check the shape of each species using VSEPR / known molecular geometry.

  2. Analyze one by one:

    (i) XeF2\mathrm{XeF_2}XeF2​

    • Central atom: Xe
    • Xe has 5 electron pairs around it: 222 bond pairs + 333 lone pairs
    • Electron pair geometry: trigonal bipyramidal
    • Lone pairs occupy equatorial positions, so the molecular shape is linear.

    (ii) I3+\mathrm{I_3^+}I3+​

    • Total valence electrons =3×7−1=20= 3\times 7 -1 = 20=3×7−1=20
    • Structure is analogous to a central I bonded to two I atoms with 222 lone pairs on central atom
    • Steric number on central I =4=4=4
    • Electron pair geometry: tetrahedral
    • Molecular shape: bent (V-shaped), not linear.

    (iii) C3O2\mathrm{C_3O_2}C3​O2​

    • Carbon suboxide structure: O=C=C=C=O\mathrm{O=C=C=C=O}O=C=C=C=O
    • Each central carbon is spspsp hybridized
    • Entire molecule is linear.

    (iv) I3−\mathrm{I_3^-}I3−​

    • Central I has 222 bond pairs and 333 lone pairs
    • Trigonal bipyramidal electron arrangement
    • Molecular shape: linear.

    (v) CO2\mathrm{CO_2}CO2​

    • Central C has two electron domains
    • spspsp hybridized
    • Shape: linear.

    (vi) SO2\mathrm{SO_2}SO2​

    • Central S has three electron domains (222 bonds + 111 lone pair)
    • Trigonal planar electron arrangement
    • Molecular shape: bent, not linear.

    (vii) BeCl2\mathrm{BeCl_2}BeCl2​

    • Central Be has two bond pairs and no lone pair
    • spspsp hybridized
    • Shape: linear.

    (viii) BCl2−\mathrm{BCl_2^-}BCl2−​

    • Valence electrons: 3+2×7+1=183 + 2\times 7 + 1 = 183+2×7+1=18
    • Central B has two bond pairs and one lone pair
    • Steric number =3=3=3
    • Electron pair geometry: trigonal planar
    • Molecular shape: bent, not linear.
  3. Linear species are:

    • XeF2\mathrm{XeF_2}XeF2​
    • C3O2\mathrm{C_3O_2}C3​O2​
    • I3−\mathrm{I_3^-}I3−​
    • CO2\mathrm{CO_2}CO2​
    • BeCl2\mathrm{BeCl_2}BeCl2​
  4. Total number of linear species: 555

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