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Chemical Bonding and Molecular Structure question

2021 · 27 Aug · Shift 1 · Q4
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Chemical Bonding and Molecular Structure question

2021 · 27 Aug · Shift 1 · Q4

JEE MainChemistryChemical Bonding and Molecular StructureMCQ+4 / −1
Match items of List-I with those of List-II :

List - I
(Property)		 List - II
(Example)
(a) Diamagnetism (i) MnO
(b) Ferrimagnetism (ii) O2{O_2}O2​
(c) Paramagnetism (iii) NaCl
(d) Antiferromagnetism (iv) Fe3O4F{e_3}{O_4}Fe3​O4​


Choose the most appropriate answer from the options given below :
  1. A
    (a)-(ii), (b)-(i), (c)-(iii), (d)-(iv)
  2. B
    (a)-(i), (b)-(iii), (c)-(iv), (d)-(ii)
  3. C
    (a)-(iii), (b)-(iv), (c)-(ii), (d)-(i)
  4. D
    (a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)
View written solutionFree

Correct answer: C

  1. Identify each magnetic property and a standard example

    We match the properties with the given substances:

    • Diamagnetism: all electrons are paired.
    • Paramagnetism: one or more unpaired electrons are present.
    • Ferrimagnetism: unequal opposite spin alignments give a net magnetic moment.
    • Antiferromagnetism: equal opposite spin alignments cancel each other.

  2. Check the examples one by one

    (iii) NaCl\mathrm{NaCl}NaCl

    In NaCl\mathrm{NaCl}NaCl, ions are Na+\mathrm{Na^+}Na+ and Cl−\mathrm{Cl^-}Cl−.

    • Na+\mathrm{Na^+}Na+ has electronic configuration [Ne][Ne][Ne]
    • Cl−\mathrm{Cl^-}Cl− has electronic configuration [Ar][Ar][Ar]

    Both have all electrons paired, so NaCl\mathrm{NaCl}NaCl is diamagnetic.

    Hence, (a)→(iii)(a) \to (iii)(a)→(iii)

    (iv) Fe3O4\mathrm{Fe_3O_4}Fe3​O4​

    Fe3O4\mathrm{Fe_3O_4}Fe3​O4​ is magnetite, a classic ferrimagnetic substance.

    Hence, (b)→(iv)(b) \to (iv)(b)→(iv)

    (ii) O2\mathrm{O_2}O2​

    Molecular oxygen has two unpaired electrons in antibonding π∗\pi^*π∗ orbitals, so it is paramagnetic.

    Hence, (c)→(ii)(c) \to (ii)(c)→(ii)

    (i) MnO\mathrm{MnO}MnO

    In MnO\mathrm{MnO}MnO, manganese is Mn2+\mathrm{Mn^{2+}}Mn2+ with configuration 3d53d^53d5. Solid MnO\mathrm{MnO}MnO shows antiferromagnetism due to antiparallel alignment of neighboring spins.

    Hence, (d)→(i)(d) \to (i)(d)→(i)

  3. Final matching

    (a)−(iii),(b)−(iv),(c)−(ii),(d)−(i)(a)-(iii),\quad (b)-(iv),\quad (c)-(ii),\quad (d)-(i)(a)−(iii),(b)−(iv),(c)−(ii),(d)−(i)

  4. Compare with options

    This corresponds to Option C.

  5. Compare with stored correct answer

    Stored correct answer is C, which matches our derived answer.

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