JEE MainChemistryChemical Bonding and Molecular StructureMCQ+4 / −1
Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R. Assertion A : Dipole-dipole interactions are the only non-covalent interactions, resulting in hydrogen bond formation. Reason R : Fluorine is the most electronegative element and hydrogen bonds in HF are symmetrical. In the light of the above statements, choose the most appropriate answer from the options given below :
- ABoth A and R are true and R is the correct explanation of A
- BA is true but R is false
- CA is false but R is true
- DBoth A and R are true but R is NOT the correct explanation of A
View written solutionFree
Correct answer: C
-
Analyze Assertion A
Assertion A says:
Dipole-dipole interactions are the only non-covalent interactions, resulting in hydrogen bond formation.
This is false.
- Hydrogen bonding is indeed a type of non-covalent interaction.
- But it is not correct to say that dipole-dipole interactions are the only non-covalent interactions.
- There are several other non-covalent interactions such as:
- London dispersion forces
- dipole-induced dipole interactions
- ion-dipole interactions
- ion-induced dipole interactions
- van der Waals interactions, etc.
Hence, Assertion A is false.
-
Analyze Reason R
Reason R says:
Fluorine is the most electronegative element and hydrogen bonds in HF are symmetrical.
Let us check both parts:
- Fluorine is the most electronegative element: this is true.
- In HF, due to the very high electronegativity of fluorine, strong hydrogen bonding occurs.
- The hydrogen-bonded species in HF are commonly treated as having symmetrical hydrogen bonding in the associated structure.
Therefore, Reason R is taken as true.
-
Match with the options
- Assertion A: False
- Reason R: True
Therefore, the correct option is:
Option C: A is false but R is true.
-
Compare with stored correct answer
Stored correct answer: C
Our derived answer matches the stored answer.
More from Chemical Bonding and Molecular Structure
- Match List - I with List - II. Choose the correct answer from the options given below : Includes table2021 · MCQ
- Match List - I with List - II : Choose the most appropriate answer from the options given below : Includes diagram2021 · MCQ
- Match items of List-I with those of List-II : Choose the most appropriate answer from the options given below : Includes table2021 · MCQ
- The number of species having non-pyramidal shape among the following is . (A) (B) NO (C) (D) CO 2021 · Numerical
- The difference between bond orders of CO and NO is where x = . (Round off to the Nearest Integer)2021 · Numerical
- The total number of electrons in all bonding molecular orbitals of is . (Round off to the nearest integer)2021 · Numerical
- The number of hydrogen bonded water molecule(s) associated with stoichiometry is .2021 · Numerical
- According to molecular orbital theory, the number of unpaired electron(s) in is :2021 · Numerical