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Chemical Bonding and Molecular Structure question

2018 · 16 Apr · Shift 1 · Q14
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Chemical Bonding and Molecular Structure question

2018 · 16 Apr · Shift 1 · Q14

JEE MainChemistryChemical Bonding and Molecular StructureMCQ+4 / −1
The incorrect geometry is represented by :
  1. A
    BF3BF_3BF3​ - trigonal planar
  2. B
    H2OH_2OH2​O - bent
  3. C
    NF3NF_3NF3​ - trigonal planar
  4. D
    AsF5AsF_5AsF5​ - trigonal bipyramidal
View written solutionFree

Correct answer: C

  1. We check the molecular geometry of each species using VSEPR theory.

  2. Option A: BF3BF_3BF3​

    • Central atom: BBB
    • Valence electrons on B=3B = 3B=3
    • It forms 3 bond pairs and has 0 lone pairs.
    • Steric number =3= 3=3
    • Geometry: trigonal planar
    • So, this is correctly represented.

  3. Option B: H2OH_2OH2​O

    • Central atom: OOO
    • Oxygen has 6 valence electrons.
    • It forms 2 bond pairs and has 2 lone pairs.
    • Steric number =4= 4=4
    • Electron pair geometry: tetrahedral
    • Molecular geometry: bent
    • So, this is correctly represented.

  4. Option C: NF3NF_3NF3​

    • Central atom: NNN
    • Nitrogen has 5 valence electrons.
    • It forms 3 bond pairs and has 1 lone pair.
    • Steric number =4= 4=4
    • Electron pair geometry: tetrahedral
    • Molecular geometry: trigonal pyramidal, not trigonal planar.
    • So, this is incorrectly represented.

  5. Option D: AsF5AsF_5AsF5​

    • Central atom: AsAsAs
    • It forms 5 bond pairs and has 0 lone pairs.
    • Steric number =5= 5=5
    • Geometry: trigonal bipyramidal
    • So, this is correctly represented.

  6. Therefore, the incorrectly represented geometry is: C\boxed{C}C​

  7. Comparison with stored correct answer:

    • Stored correct answer: CCC
    • Derived answer: CCC
    • They match.
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