- A, ,
- B, , XeF
- C, ,
- D, ,
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Correct answer: B
- Determine the molecular shape of each species using VSEPR theory.
We compare the shapes within each option.
- Option A: , ,
-
: Sulfur has 5 electron pairs around it bond pairs lone pair
Electronic geometry: trigonal bipyramidal
Molecular shape: see-saw -
: Xenon has 6 electron pairs around it bond pairs lone pairs
Electronic geometry: octahedral
Molecular shape: square planar -
: Carbon has 4 bond pairs, no lone pair
Molecular shape: tetrahedral
These are not identical.
- Option B: , ,
-
: Chlorine has 5 electron pairs bond pairs lone pairs
Electronic geometry: trigonal bipyramidal
Molecular shape: T-shaped -
: Count electron domains on Xe.
Xenon has 8 valence electrons. Around Xe: one bond, two bonds, and two lone pairs.
Thus steric number bonded regions lone pairs
Electronic geometry: trigonal bipyramidal
Molecular shape: T-shaped -
:
Valence electrons on Xe: Add 3 fluorine atoms contributing one electron each in bond framework consideration; after bonding, Xe effectively has 5 electron domains bond pairs lone pairs.
So steric number
Electronic geometry: trigonal bipyramidal
Molecular shape: T-shaped
Thus all three have identical T-shaped geometry.
- Option C: , ,
- : trigonal planar
- : trigonal pyramidal
- : Xenon has 3 bond pairs and 1 lone pair trigonal pyramidal
Not identical.
- Option D: , ,
- : trigonal bipyramidal
- : bond pairs lone pair square pyramidal
- : Xe has 4 bonded regions O, F and 1 lone pair trigonal bipyramidal electron arrangement, see-saw shape
Not identical.
- Conclusion
The only group in which all molecules have the same shape is:
So the molecules , , and are all T-shaped.
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