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Chemical Bonding and Molecular Structure question

2002 · Shift 0 · Q59
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Chemical Bonding and Molecular Structure question

2002 · Shift 0 · Q59

JEE MainChemistryChemical Bonding and Molecular StructureMCQ+4 / −1
Which of the following are arranged in an increasing order of their bond strengths?
  1. A
    O2−O_2^-O2−​< O2O_2O2​ <O2+O_2^+O2+​<O22−O_2^{2-}O22−​
  2. B
    O22−O_2^{2-}O22−​<O2−O_2^-O2−​<O2O_2O2​<O2+O_2^{+}O2+​
  3. C
    O2−O_2^-O2−​<O22−O_2^{2-}O22−​<O2O_2O2​<O2+O_2^{+}O2+​
  4. D
    O2+O_2^{+}O2+​<O2O_2O2​<O2−O_2^-O2−​<O22−O_2^{2-}O22−​
View written solutionFree

Correct answer: B

  1. Bond strength and bond order

For diatomic molecules like oxygen species, bond strength increases with bond order.

So we first find the bond order of each species.

  1. Molecular orbital configuration of O2O_2O2​

For O2O_2O2​ and related species, the relevant MO filling is:

(σ2s)2(σ∗2s)2(σ2pz)2(π2px)2(π2py)2(π∗2px)1(π∗2py)1(\sigma 2s)^2(\sigma^*2s)^2(\sigma 2p_z)^2(\pi 2p_x)^2(\pi 2p_y)^2(\pi^* 2p_x)^1(\pi^* 2p_y)^1(σ2s)2(σ∗2s)2(σ2pz​)2(π2px​)2(π2py​)2(π∗2px​)1(π∗2py​)1

Thus, for O2O_2O2​:

  • Bonding electrons in valence MOs =8= 8=8
  • Antibonding electrons in valence MOs =4= 4=4

Hence,

Bond order of O2=Nb−Na2=8−42=2\text{Bond order of } O_2 = \frac{N_b-N_a}{2} = \frac{8-4}{2}=2Bond order of O2​=2Nb​−Na​​=28−4​=2
  1. Bond order of O2+O_2^+O2+​

Removing one electron from O2O_2O2​ removes it from an antibonding π∗\pi^*π∗ orbital.

So antibonding electrons decrease by 1:

Bond order of O2+=8−32=2.5\text{Bond order of } O_2^+ = \frac{8-3}{2} = 2.5Bond order of O2+​=28−3​=2.5
  1. Bond order of O2−O_2^-O2−​

Adding one electron to O2O_2O2​ adds it to an antibonding π∗\pi^*π∗ orbital.

So antibonding electrons increase by 1:

Bond order of O2−=8−52=1.5\text{Bond order of } O_2^- = \frac{8-5}{2} = 1.5Bond order of O2−​=28−5​=1.5
  1. Bond order of O22−O_2^{2-}O22−​

Adding two electrons to O2O_2O2​ fills both antibonding π∗\pi^*π∗ orbitals further.

So antibonding electrons increase by 2:

Bond order of O22−=8−62=1\text{Bond order of } O_2^{2-} = \frac{8-6}{2} = 1Bond order of O22−​=28−6​=1
  1. Arrange in increasing order of bond strength

Since bond strength ∝\propto∝ bond order:

O22−<O2−<O2<O2+O_2^{2-} < O_2^- < O_2 < O_2^+O22−​<O2−​<O2​<O2+​
  1. Match with options

This corresponds to Option B.

Previous

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