1. List the given molecules and count lone pairs on the central atom

We need the molecule which satisfies both:

• it has nonzero dipole moment, and
• it has the highest number of lone pairs on the central atom.

Let us check each one.

2. Analyze each molecule

(i) $\mathrm{SO_2}$

• Central atom: S
• Total electron domains around S: 3
• Structure is bent.
• Lone pairs on S = 1
• Because of bent shape, dipole moment is nonzero.
• Hybridization of S is approximately $\mathrm{sp^2}$.

(ii) $\mathrm{NF_3}$

• Central atom: N
• N has 3 bond pairs and 1 lone pair.
• Lone pairs on N = 1
• Shape: trigonal pyramidal
• Dipole moment is nonzero.
• Hybridization: $\mathrm{sp^3}$

(iii) $\mathrm{NH_3}$

• Central atom: N
• 3 bond pairs and 1 lone pair
• Lone pairs on N = 1
• Shape: trigonal pyramidal
• Dipole moment is nonzero.
• Hybridization: $\mathrm{sp^3}$

(iv) $\mathrm{XeF_2}$

• Central atom: Xe
• Xe has 2 bond pairs and 3 lone pairs.
• Lone pairs on Xe = 3
• Shape: linear
• Due to linear symmetry, dipole moment is zero.
• So it does not satisfy the condition.
• Hybridization: $\mathrm{sp^3d}$

(v) $\mathrm{ClF_3}$

• Central atom: Cl
• Cl has 3 bond pairs and 2 lone pairs.
• Lone pairs on Cl = 2
• Shape: T-shaped
• Dipole moment is nonzero.
• Hybridization: $\mathrm{sp^3d}$

(vi) $\mathrm{SF_4}$

• Central atom: S
• S has 4 bond pairs and 1 lone pair.
• Lone pairs on S = 1
• Shape: seesaw
• Dipole moment is nonzero.
• Hybridization: $\mathrm{sp^3d}$

3. Select the molecule with nonzero dipole moment and highest number of lone pairs

From the above:

• $\mathrm{SO_2}$: 1 lone pair, polar
• $\mathrm{NF_3}$: 1 lone pair, polar
• $\mathrm{NH_3}$: 1 lone pair, polar
• $\mathrm{XeF_2}$: 3 lone pairs, but nonpolar
• $\mathrm{ClF_3}$: 2 lone pairs, polar
• $\mathrm{SF_4}$: 1 lone pair, polar

The molecule satisfying the condition is: $\mathrm{ClF_3}$ because it has the highest number of lone pairs (2) among molecules with nonzero dipole moment.

4. Find its hybridization

For $\mathrm{ClF_3}$:

• Total electron pairs around Cl = 5
• Steric number = 5
• Hybridization = $\mathrm{sp^3d}$

5. Match with options

$\mathrm{sp^3d}$ corresponds to Option D.

6. Comparison with stored answer

Stored correct answer: D

Our derived answer: D

So, the derived answer agrees with the stored answer.