Identify each reaction of glucose

We match each reagent with the product formed.

(A) Glucose + HI

On prolonged heating with excess HI, glucose gets completely reduced to $n$-hexane.

$\text{Glucose} \xrightarrow[\text{heat}]{HI} \text{Hexane}$

So, $(A) \to (IV)$

(B) Glucose + $Br_2$ water

Bromine water is a mild oxidizing agent. It oxidizes the aldehyde group of glucose to a carboxylic acid, giving gluconic acid.

$\text{Glucose} \xrightarrow{Br_2/H_2O} \text{Gluconic acid}$

So, $(B) \to (I)$

(C) Glucose + acetic anhydride

Glucose has five $-OH$ groups, so with acetic anhydride it forms glucose pentacetate.

$\text{Glucose} \xrightarrow{(CH_3CO)_2O} \text{Glucose pentacetate}$

So, $(C) \to (II)$

(D) Glucose + $HNO_3$

Nitric acid is a strong oxidizing agent. It oxidizes both the aldehyde group and the terminal primary alcohol group to carboxylic acids, giving saccharic acid.

$\text{Glucose} \xrightarrow{HNO_3} \text{Saccharic acid}$

So, $(D) \to (III)$

Final matching

$(A)-(IV),\ (B)-(I),\ (C)-(II),\ (D)-(III)$

Compare with options

This corresponds to Option A.

Comparison with stored correct answer

Stored correct answer = A

Our derived answer = A

Hence, they agree.